Showing posts with label puzzles. Show all posts
Showing posts with label puzzles. Show all posts

Tuesday, October 14, 2008

Puzzle: Elevator problem

Question: A man lives on the twelfth floor of an apartment building. Every morning he takes the elevator down to the lobby and leaves the building. In the evening, he gets into the elevator, and, if there is someone else in the elevator -- or if it was raining that day -- he goes back to his floor directly. Otherwise, he goes to the tenth floor and walks up two flights of stairs to his apartment.

Answer: The man is a dwarf. He can't reach the upper elevator buttons, but he can ask people to push them for him. He can also push them with his umbrella.

Puzzle: 100 doors in a row

You have 100 doors in a row that are all initially closed. you make 100 passes by the doors starting with the first door every time. the first time through you visit every door and toggle the door (if the door is closed, you open it, if its open, you close it). the second time you only visit every 2nd door (door #2, #4, #6). the third time, every 3rd door (door #3, #6, #9), etc, until you only visit the 100th door.

for example, after the first pass every door is open. on the second pass you only visit the even doors (2,4,6,8...) so now the even doors are closed and the odd ones are opened. the third time through you will close door 3 (opened from the first pass), open door 6 (closed from the second pass), etc..

question: what state are the doors in after the last pass? which are open which are closed?





Solution: you can figure out that for any given door, say door #42, you will visit it for every divisor it has. so 42 has 1 & 42, 2 & 21, 3 & 14, 6 & 7. so on pass 1 i will open the door, pass 2 i will close it, pass 3 open, pass 6 close, pass 7 open, pass 14 close, pass 21 open, pass 42 close. for every pair of divisors the door will just end up back in its initial state. so you might think that every door will end up closed? well what about door #9. 9 has the divisors 1 & 9, 3 & 3. but 3 is repeated because 9 is a perfect square, so you will only visit door #9, on pass 1, 3, and 9... leaving it open at the end. only perfect square doors will be open at the end.


Puzzle: get exactly 2 liters with the 4 ltr and 7 ltr jars

The Problem:

You've got two jars, one of them fits exactly 7 liters, the other one fits exactly 4 liters. How could you get exactly 2 liters with these two jars? You have unlimited supply of water and you are allowed to spoil some water.


The Solution:

7 0 fill the 7 ltr jar completely
3 4 fill the 4 ltr jar using the 7 ltr one completely
3 0 empty the 4 ltr jar
0 3 fill all water from 7 ltr jar to 4 ltr water
7 3 fill the 7 ltr jar completely
6 4 fill 4 ltr jar from 7 ltr one completely
6 0 empty the 4 ltr jar
2 4 fill 4 ltr jar from 7 ltr one completely
2 0 empty the 4 ltr jar

Now you have exactly 2 ltrs in 7 ltr jar